(C) The capacitance $C$ of a spherical capacitor with inner radius $a$ and outer radius $b$ is given by $C = 4\pi\epsilon_0 \frac{ab}{b - a}$.Given, t

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(C) The capacitance $C$ of a spherical capacitor with inner radius $a$ and outer radius $b$ is given by $C = 4\pi\epsilon_0 \frac{ab}{b - a}$.Given, the radius of the outer sphere $b = R$.The difference in radii is $b - a = x$, so the inner radius $a = R - x$.Substituting these values into the formula, we get $C = 4\pi\epsilon_0 \frac{(R - x)R}{x}$.Since $4\pi\epsilon_0$ is a constant, the capacity $C$ is proportional to $\frac{R(R - x)}{x}$.

Class 12 Physics Electric Potential and Capacitance Basic of Capacitor and type of capacitor (Spherical, Cylindrical)

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In a spherical condenser, the radius of the outer sphere is $R$. The difference in the radii of the outer and inner sphere is $x$. Its capacity is proportional to:

A
$\frac{xR}{R - x}$
B
$\frac{x(R - x)}{R}$
C
$\frac{R(R - x)}{x}$
D
$\frac{R}{x}$

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Electric Potential and Capacitance

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Basic of Capacitor and type of capacitor (Spherical, Cylindrical)

For the shown situation,in the steady state condition,the ratio of the charge stored in the first capacitor to the charge stored in the $n^{th}$ capacitor is:

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When a $0.75 \mu F$ capacitor is charged to a voltage of $20 \ V$,then the magnitude of charge on each plate is (in $\mu C$)

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If the energy stored in a spherical conductor having a charge of $12 \mu C$ is $6 \ J$,then the radius of the spherical conductor is (in $cm$)

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The graph shows the variation of voltage $V$ across the plates of two capacitors $A$ and $B$ versus the charge $Q$ stored in them. Then:

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In a spherical condenser, the radius of the outer sphere is $R$. The difference in the radii of the outer and inner sphere is $x$. Its capacity is proportional to:

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For the shown situation,in the steady state condition,the ratio of the charge stored in the first capacitor to the charge stored in the $n^{th}$ capacitor is:

$8$ small drops,each of capacitance $C$,coalesce to form a single large drop. The capacitance of the large drop will be ........ $C$.

When a $0.75 \mu F$ capacitor is charged to a voltage of $20 \ V$,then the magnitude of charge on each plate is (in $\mu C$)

If the energy stored in a spherical conductor having a charge of $12 \mu C$ is $6 \ J$,then the radius of the spherical conductor is (in $cm$)

The graph shows the variation of voltage $V$ across the plates of two capacitors $A$ and $B$ versus the charge $Q$ stored in them. Then:

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