In a survey of 60 people,it was found that 25 | vedclass

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(A) Let $n(H)=25, n(T)=26, n(I)=26$.Given intersections: $n(H \cap I)=9, n(H \cap T)=11, n(T \cap I)=8, n(H \cap T \cap I)=3$.Let $x, y, z$ be the num

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$30$

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(A) Let $n(H)=25, n(T)=26, n(I)=26$.Given intersections: $n(H \cap I)=9, n(H \cap T)=11, n(T \cap I)=8, n(H \cap T \cap I)=3$.Let $x, y, z$ be the number of people who read only $H, T, I$ respectively.Number of people reading only two newspapers:Only $H$ and $T = n(H \cap T) - n(H \cap T \cap I) = 11 - 3 = 8$.Only $H$ and $I = n(H \cap I) - n(H \cap T \cap I) = 9 - 3 = 6$.Only $T$ and $I = n(T \cap I) - n(H \cap T \cap I) = 8 - 3 = 5$.Number of people reading only one newspaper:Only $H = n(H) - (8 + 6 + 3) = 25 - 17 = 8$.Only $T = n(T) - (8 + 5 + 3) = 26 - 16 = 10$.Only $I = n(I) - (6 + 5 + 3) = 26 - 14 = 12$.Total reading exactly one newspaper $= 8 + 10 + 12 = 30$.

In a survey of $60$ people,it was found that $25$ people read newspaper $H$,$26$ read newspaper $T$,$26$ read newspaper $I$,$9$ read both $H$ and $I$,$11$ read both $H$ and $T$,$8$ read both $T$ and $I$,and $3$ read all three newspapers. Find the number of people who read exactly one newspaper.

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