In an $L-C-R$ circuit,the capacitance is changed from $C$ to $4 C$. For the same resonant frequency,the inductance should be changed from $L$ to

Consider the parallel $LCR$ circuit shown in the figure. Find the net current $i$ and the phase of $i$. Show that $i = \frac{V}{Z}$. Find the impedance $Z$ for this circuit.

In the circuit diagram shown,$X_C = 100 \, \Omega$,$X_L = 200 \, \Omega$,and $R = 100 \, \Omega$. The source voltage is $V = 200 \sin(\omega t) \, \text{V}$. The effective $(RMS)$ current through the source is:

$A$ $750\, Hz$,$20\, V$ (rms) source is connected to a resistance of $100\, \Omega$,an inductance of $0.1803\, H$,and a capacitance of $10\, \mu F$,all in series. The time in which the resistance (heat capacity $2\, J/^{\circ}C$) will get heated by $10^{\circ}C$ (assume no loss of heat to the surroundings) is close to $.....s$.

The reading of the ammeter in the circuit is ............ $A$.

In an a.c. circuit containing $L, C$ and $R$ in series,the ratio of apparent power to the true power is ($Z$ and $R$ are the impedance and resistance respectively,$\phi$ = phase angle).