In an examination,65 % of students pass in Hi | vedclass

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(A) Let $H$ be the set of students who passed in History and $L$ be the set of students who passed in Hindi.Given: $n(H) = 65 \%$,$n(L) = 55 \%$.Perce

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(A) Let $H$ be the set of students who passed in History and $L$ be the set of students who passed in Hindi.Given: $n(H) = 65 \%$,$n(L) = 55 \%$.Percentage of students who failed in both subjects $= 5 \%$.Therefore,the percentage of students who passed in at least one subject $= 100 \% - 5 \% = 95 \%$.Using the formula $n(H \cup L) = n(H) + n(L) - n(H \cap L)$:$95 \% = 65 \% + 55 \% - n(H \cap L)$.$95 \% = 120 \% - n(H \cap L)$.$n(H \cap L) = 120 \% - 95 \% = 25 \%$.Thus,$25 \%$ of students passed in both subjects.

In an examination,$65 \%$ of students pass in History and $55 \%$ of students pass in Hindi. If $5 \%$ of students fail in both subjects,what is the percentage of students who passed in both subjects?

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