In the case of the displacement method of len | vedclass

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(A) In the displacement method,a lens is moved between a fixed object and a screen to obtain a sharp image at two different positions.Let the distance

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$1$

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(A) In the displacement method,a lens is moved between a fixed object and a screen to obtain a sharp image at two different positions.Let the distance between the object and the screen be $D$,and the focal length of the lens be $f$.For the first position of the lens,let the magnification be $m_1 = \frac{v_1}{u_1}$.For the second position of the lens,the object distance and image distance are interchanged,so $u_2 = v_1$ and $v_2 = u_1$.The magnification for the second position is $m_2 = \frac{v_2}{u_2} = \frac{u_1}{v_1}$.Multiplying the two magnifications,we get $m_1 	imes m_2 = \left(\frac{v_1}{u_1}ight) 	imes \left(\frac{u_1}{v_1}ight) = 1$.

In the case of the displacement method of lenses,the product of magnification in both cases is

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