In the charring process, concentrated sulfuri | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The chemical reaction for the charring of sugar $(C_{12}H_{22}O_{11})$ by concentrated sulfuric acid $(H_2SO_4)$ is:$C_{12}H_{22}O_{11} \xrightarr

Vedclass · Accepted Answer

$A$ dehydrating agent

Vedclass · Answer

(C) The chemical reaction for the charring of sugar $(C_{12}H_{22}O_{11})$ by concentrated sulfuric acid $(H_2SO_4)$ is:$C_{12}H_{22}O_{11} \xrightarrow{conc. H_2SO_4} 12C + 11H_2O$In this reaction, concentrated $H_2SO_4$ removes the elements of water ($H$ and $O$ in the ratio $2:1$) from the sugar molecule.Since it removes water molecules from the compound, it acts as a dehydrating agent.

In the charring process, concentrated sulfuric acid reacts with sugar to give sugar charcoal. What is the role of conc. $H_2SO_4$ in this reaction?

Similar Questions

Explain the structure of water.

Heavy water $(D_2O)$ is used as:

Which of the following is not true about the $H_2O$ molecule?

Which of the following statements is $INCORRECT$?

How is the oxygen atom surrounded in ice?

Vedclass Test Series

Exam Paper Generator

Online Exam Module