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(B) The given circuit consists of a $5 	ext{ V}$ $DC$ source, a silicon diode, and a resistor of $200 	ext{ } \Omega$ connected in series.Since the

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$21.5$

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(B) The given circuit consists of a $5 	ext{ V}$ $DC$ source, a silicon diode, and a resistor of $200 	ext{ } \Omega$ connected in series.Since the diode is forward-biased, it will conduct current when the applied voltage exceeds its knee voltage.The effective voltage across the resistor $(V_R)$ is given by:$V_R = V_{	ext{source}} - V_{	ext{knee}}$$V_R = 5 	ext{ V} - 0.7 	ext{ V} = 4.3 	ext{ V}$Using Ohm's law, the current $(I)$ flowing through the circuit is:$I = \frac{V_R}{R}$$I = \frac{4.3 	ext{ V}}{200 	ext{ } \Omega} = 0.0215 	ext{ A}$To convert the current into milliamperes (mA):$I = 0.0215 	imes 1000 	ext{ mA} = 21.5 	ext{ mA}$Therefore, the reading in the milliammeter is $21.5 	ext{ mA}$.

In the following electrical circuit, the reading in the milliammeter is (Take knee voltage of silicon diode $= 0.7 \text{ V}$) (in $\text{ mA}$)

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