(C) In the $CH_3-C^* \equiv C^*-CH_3$ molecule,both $C^*$ carbon atoms are bonded to one other carbon atom via a single bond and to each other via a t

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(C) In the $CH_3-C^* \equiv C^*-CH_3$ molecule,both $C^*$ carbon atoms are bonded to one other carbon atom via a single bond and to each other via a triple bond.Each $C^*$ atom is attached to two atoms in total (one $C$ and one $C$),and there are no lone pairs on the carbon atoms.The steric number for each $C^*$ atom is $2 + 0 = 2$.$A$ steric number of $2$ corresponds to $sp$ hybridization.Therefore,the correct answer is Option $(C)$ $sp$ orbital.

Class 11 Chemistry 8-1.Organic Chemistry : Classification and Nomenclature of Organic compounds Bonding and hybridisation in organic compounds

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In the following molecule,the two carbon atoms marked by asterisk $()$ possess the following type of hybridized orbitals: $CH_3-C^ \equiv C^*-CH_3$

A
$sp^3$ orbital
B
$sp^2$ orbital
C
$sp$ orbital
D
$s$ orbital

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8-1.Organic Chemistry : Classification and Nomenclature of Organic compounds

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Bonding and hybridisation in organic compounds

What are the hybridisation states of each carbon atom in the following compounds?
$CH_2=C=O, \quad CH_3-CH=CH_2, \quad (CH_3)_2CO, \quad CH_2=CH-CN, \quad C_6H_6$

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In the molecule $HC^{1} \equiv C^{2} - CH^{3} = CH^{4} - CH_{3}^{5}$,which carbon atom exhibits the lowest electronegativity?

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What is the hybridization of carbon atoms at positions $1$,$3$,and $5$ in the compound $CH_3-CH=CH-CH_2-C \equiv CH$?

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The hybridization of carbon involved in the $C_2-C_3$ single bond in the molecule $CH \equiv C-CH=CH_2$ is

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In the molecule $CH_2=C=CH-CH_3$ (where the atoms are numbered $1, 2, 3,$ and $4$ respectively),the hybridization of carbon $1, 2, 3,$ and $4$ are:

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In the following molecule,the two carbon atoms marked by asterisk $(*)$ possess the following type of hybridized orbitals: $CH_3-C^* \equiv C^*-CH_3$

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What are the hybridisation states of each carbon atom in the following compounds?$CH_2=C=O, \quad CH_3-CH=CH_2, \quad (CH_3)_2CO, \quad CH_2=CH-CN, \quad C_6H_6$

In the molecule $HC^{1} \equiv C^{2} - CH^{3} = CH^{4} - CH_{3}^{5}$,which carbon atom exhibits the lowest electronegativity?

What is the hybridization of carbon atoms at positions $1$,$3$,and $5$ in the compound $CH_3-CH=CH-CH_2-C \equiv CH$?

The hybridization of carbon involved in the $C_2-C_3$ single bond in the molecule $CH \equiv C-CH=CH_2$ is

In the molecule $CH_2=C=CH-CH_3$ (where the atoms are numbered $1, 2, 3,$ and $4$ respectively),the hybridization of carbon $1, 2, 3,$ and $4$ are:

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In the following molecule,the two carbon atoms marked by asterisk $()$ possess the following type of hybridized orbitals: $CH_3-C^ \equiv C^*-CH_3$

What are the hybridisation states of each carbon atom in the following compounds?
$CH_2=C=O, \quad CH_3-CH=CH_2, \quad (CH_3)_2CO, \quad CH_2=CH-CN, \quad C_6H_6$