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(D) The reaction sequence is as follows:$1$. Hydration of the alkyne $HC \equiv C-(CH_2)_{15}-CO_2Et$ with $Hg^{2+}/H_3O^+$ gives a ketone.$2$. Clemme

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(D) The reaction sequence is as follows:$1$. Hydration of the alkyne $HC \equiv C-(CH_2)_{15}-CO_2Et$ with $Hg^{2+}/H_3O^+$ gives a ketone.$2$. Clemmensen reduction $(Zn(Hg)/HCl)$ reduces the ketone to an alkane chain.$3$. Acidic hydrolysis $(H_3O^+, \Delta)$ converts the ester to stearic acid $(C_{17}H_{35}COOH)$,which is product $P$.$4$. Glycerol reacts with $3$ moles of stearic acid to form glyceryl tristearate $(Q)$.$5$. Saponification of $1$ mole of $Q$ with $NaOH$ yields $3$ moles of sodium stearate $(C_{17}H_{35}COONa)$.$6$. Treatment with $CaCl_2$ converts $3$ moles of sodium stearate into $\frac{3}{2}$ moles of calcium stearate $(R = (C_{17}H_{35}COO)_2Ca)$.$7$. Molar mass of $R = (17 	imes 12 + 35 	imes 1 + 44) 	imes 2 + 40 = (204 + 35 + 44) 	imes 2 + 40 = 283 	imes 2 + 40 = 566 + 40 = 606 \ g/mol$.$8$. Amount of $R = \frac{3}{2} 	imes 606 \ g = 909 \ g$.

Similar Questions

What are the products formed at the anode during Kolbe synthesis?

$CH_3COOH \xrightarrow{LiAlH_4} A$
$A + CH_3COOH \xrightarrow{H_3O^+} B + H_2O$
In the above reactions,'$A$' and '$B$' respectively are:

The major products $A$ and $B$ in the following set of reactions are:

$CH_3-C(=O)-OH$ $\xrightarrow{NaH^{14}CO_3} (A) (\text{gas})$ $\xrightarrow[(ii) H_3O^{+}]{(i) PhMgBr} (B)$
$CH_3-S(=O)_2-OH$ $\xrightarrow{NaH^{14}CO_3} (C) (\text{gas})$ $\xrightarrow[(ii) H_3O^{+}]{(i) PhMgBr} (D)$
Product $(B)$ and $(D)$ in the above reaction are:

In the reaction sequence,$[X]$ is a ketone:
$[X] \xrightarrow{KMnO_4/OH^{-}/\Delta} HOOC-(CH_2)_3-CH(CH_3)-COOH$
$[X]$ will be:

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