In the fundamental mode,the time taken by the wave to reach the closed end of an air-filled pipe is $0.01 \ s$. The fundamental frequency is (in $Hz$)

In a resonance tube of length $0.8 \,m$, an air column vibrates with a source of frequency $375 \,Hz$ for a certain height of water from the bottom of the tube. What is the water level corresponding to the fundamental frequency (in $\,m$)? (Neglect end correction, speed of sound in air = $330 \,m/s$)

The fundamental frequency of an air column in a pipe closed at one end is $100 \ Hz$. If the same pipe is open at both the ends,the frequencies produced in $Hz$ are

What is the minimum length of a tube,open at both ends,that resonates with a tuning fork of frequency $350 \ Hz$? [Velocity of sound in air $= 350 \ m/s$] ..... $cm$

The two nearest harmonics of a tube closed at one end and open at the other end are $220\, Hz$ and $260\, Hz$. What is the fundamental frequency of the system in $Hz$?

$A$ glass tube is open at both ends. $A$ tuning fork of frequency $f$ resonates with the air column inside the tube. Now,the tube is placed vertically inside water so that half the length of the tube is filled with water. Now,the air column inside the tube is in unison with another fork of frequency $f^{\prime}$. Then,