In the given circuit,the Zener breakdown voltage is $8 \ V$. If the power of the Zener diode is $1.6 \ W$,the value of $R$ is (in $\Omega$)

Take the breakdown voltage of the zener diode used in the given circuit as $6\, V$. For the input voltage shown in the figure below, the time variation of the output voltage is: (Graphs drawn are schematic and not to scale)

$A$ Zener diode in the circuit shown has a knee current of $5\,mA$ and a maximum allowed power dissipation of $300\,mW$. What are the minimum and maximum load currents that can be drawn safely from the circuit, keeping the output voltage $V_0$ constant at $6\,V$?

$A$ Zener diode having a breakdown voltage of $5.6 \ V$ is connected in reverse bias with a battery of emf $10 \ V$ and a resistance of $100 \ \Omega$ in series. The current flowing through the Zener diode is (in $mA$)

If the voltage between the terminals $A$ and $B$ is $17\ V$ and the Zener breakdown voltage is $9\ V$,then the potential voltage across $R$ is.......$V$.

Two Zener diodes ($A$ and $B$) having breakdown voltages of $6\, V$ and $4\, V$ respectively,are connected as shown in the circuit below. The output voltage $V_{0}$ variation with input voltage linearly increasing with time,is given by: $(V_{\text{input}} = 0\, V$ at $t = 0)$ (figures are qualitative).