In the given reaction,[X] is: | vedclass

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(A) The starting material is a halohydrin,specifically $2$-chlorocyclohexanol,where the $-OH$ and $-Cl$ groups are in a trans configuration.When treat

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$A$ cyclic ether (epoxide)

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(A) The starting material is a halohydrin,specifically $2$-chlorocyclohexanol,where the $-OH$ and $-Cl$ groups are in a trans configuration.When treated with a base like $NaOH$,the hydroxide ion deprotonates the hydroxyl group to form an alkoxide ion.This alkoxide ion then performs an intramolecular $S_N2$ displacement of the chloride ion from the adjacent carbon.Because the $-OH$ and $-Cl$ groups are trans to each other,they are in the anti-periplanar geometry required for the $S_N2$ reaction to occur.This results in the formation of an epoxide (cyclohexene oxide) as the product $[X]$.

In the given reaction,$[X]$ is:

Similar Questions

The product $(C)$ in the below mentioned reaction is:
$CH_3-CH_2-CH_2-Br$ $\xrightarrow[\Delta]{KOH_{(alc)}} A$ $\xrightarrow{HBr} B$ $\xrightarrow[KOH_{(aq)}]{\Delta} C$

Dehydration of an alcohol $(A)$ gives an alkene. Ozonolysis of one molecule of this alkene yields two molecules of acetaldehyde. Identify the alcohol $(A)$.

Compound '$A$' reacts with $PCl_5$ to give '$B$',which on treatment with $KCN$ followed by hydrolysis gives propanoic acid as the product. What is '$A$'?

Explain: Ethanol has a higher boiling point than methoxymethane.

The reaction shown below is an example of:
$CH_2=CH-COOCH_3 + CH_3CH_2CH_2OH \xrightarrow{\text{Conc. } HCl} CH_2=CH-COOCH_2CH_2CH_3 + CH_3OH$

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