Dehydration of an alcohol (A) gives an alkene | vedclass

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(D) $1$. Ozonolysis of an alkene yielding two molecules of acetaldehyde $(CH_3CHO)$ indicates that the alkene is $CH_3CH=CHCH_3$ (but$-2-$ene).$2$. Th

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$CH_3CH_2CH(OH)CH_3$

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(D) $1$. Ozonolysis of an alkene yielding two molecules of acetaldehyde $(CH_3CHO)$ indicates that the alkene is $CH_3CH=CHCH_3$ (but$-2-$ene).$2$. The dehydration of an alcohol $(A)$ produces but$-2-$ene.$3$. $CH_3CH_2CH(OH)CH_3$ (butan$-2-$ol) undergoes dehydration to form but$-2-$ene as the major product according to Saytzeff's rule.$4$. Therefore,the alcohol $(A)$ is butan$-2-$ol,which is $CH_3CH_2CH(OH)CH_3$.

Dehydration of an alcohol $(A)$ gives an alkene. Ozonolysis of one molecule of this alkene yields two molecules of acetaldehyde. Identify the alcohol $(A)$.

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