In the Mean Value Theorem,$f'(c) = \frac{f(b) - f(a)}{b - a}$. If $a = 0$,$b = \frac{1}{2}$,and $f(x) = x(x - 1)(x - 2)$,then the value of $c$ is:

  • A
    $1 - \frac{\sqrt{15}}{6}$
  • B
    $1 - \frac{\sqrt{13}}{6}$
  • C
    $1 - \frac{\sqrt{21}}{6}$
  • D
    $1 + \frac{\sqrt{21}}{6}$

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