In the sulphur estimation,$0.20 \ g$ of a pure organic compound gave $0.40 \ g$ of barium sulphate. The percentage of sulphur in the compound is $.......... \times 10^{-1} \%$. $(Molar \ mass : O=16, S=32, Ba=137 \ g \ mol^{-1})$

$0.5 \ g$ of an organic compound containing phosphorus was heated with conc. $HNO_3$ in a Carius tube. The phosphoric acid thus formed was precipitated with magnesia mixture $[MgNH_4PO_4]$,which on ignition gave a residue of $1.0 \ g$ of magnesium pyrophosphate $(Mg_2P_2O_7)$. The percentage of phosphorus in the organic compound is:

$1.4 \ g$ of an organic compound was digested according to Kjeldahl's method and the ammonia evolved was absorbed in $60 \ mL$ of $M/10 \ H_2SO_4$ solution. The excess sulphuric acid required $20 \ mL$ of $M/10 \ NaOH$ solution for neutralization. The percentage of nitrogen in the compound is

$A$ student has been given $0.314 \ g$ of an organic compound and asked to estimate Sulphur. During the experiment, the student has obtained $0.4813 \ g$ of barium sulphate. The percentage of sulphur present in the compound is . . . . . .
(Given Molar mass in $g \ mol^{-1}$: $S = 32$, $BaSO_4 = 233$) (in $\%$)

In the quantitative estimation of sulfur in an organic compound,the amount of sulfur is determined in the form of which substance?

Which method is used for the quantitative estimation of nitrogen in an organic compound?