In trapezium ABCD,AB parallel CD. If angle A | vedclass

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(A) In a trapezium $ABCD$,the sides $AB$ and $CD$ are parallel $(AB \parallel CD)$.According to the properties of parallel lines,the consecutive inter

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$100$

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(A) In a trapezium $ABCD$,the sides $AB$ and $CD$ are parallel $(AB \parallel CD)$.According to the properties of parallel lines,the consecutive interior angles (also known as co-interior angles) between parallel lines are supplementary.Therefore,$\angle A + \angle D = 180^{\circ}$ and $\angle B + \angle C = 180^{\circ}$.Given $\angle A = 80^{\circ}$,we can find $\angle D$ as follows:$\angle A + \angle D = 180^{\circ}$$80^{\circ} + \angle D = 180^{\circ}$$\angle D = 180^{\circ} - 80^{\circ}$$\angle D = 100^{\circ}$.

In trapezium $ABCD$,$AB \parallel CD$. If $\angle A = 80^{\circ}$ and $\angle B = 75^{\circ}$,then find $\angle D$. (in $^{\circ}$)

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