In which of the following molecules is the N | vedclass

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(C) $1$. In the nitronium ion $(NO_2^ )$,the $N$ atom is $sp$ hybridized (linear geometry).$2$. In the nitrate ion $(NO_3^-)$,the $N$ atom is $sp^2$ h

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Trisilylamine $(N(SiH_3)_3)$

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(C) $1$. In the nitronium ion $(NO_2^ )$,the $N$ atom is $sp$ hybridized (linear geometry).$2$. In the nitrate ion $(NO_3^-)$,the $N$ atom is $sp^2$ hybridized (trigonal planar geometry).$3$. In trisilylamine $(N(SiH_3)_3)$,the $N$ atom is $sp^3$ hybridized (pyramidal geometry) because the lone pair on $N$ is donated into the empty $d$-orbitals of $Si$ ($p\pi-d\pi$ back bonding),but the steric arrangement remains $sp^3$.$4$. In borazine $(B_3N_3H_6)$,the $N$ atoms are $sp^2$ hybridized (planar ring structure).$5$. Therefore,the $N$ atom is not $sp^2$ hybridized in both the nitronium ion $(sp)$ and trisilylamine $(sp^3)$. However,in the context of standard multiple-choice questions where only one answer is expected,trisilylamine is the classic example of $sp^3$ hybridization due to the lone pair involvement in back bonding.

In which of the following molecules is the $N$ atom not $sp^2$ hybridized?

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