(A) The reaction between phthalic acid and ethylamine $(C_2H_5NH_2)$ under heating $(\Delta)$ involves the formation of an amide linkage. Initially,th

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(A) The reaction between phthalic acid and ethylamine $(C_2H_5NH_2)$ under heating $(\Delta)$ involves the formation of an amide linkage. Initially,the acid-base reaction forms a salt,which upon further heating undergoes dehydration to form the cyclic imide,$N$-ethylphthalimide. The reaction is: Phthalic acid $C_2H_5NH_2 \xrightarrow{\Delta} N$-ethylphthalimide $2H_2O$.

Class 12 Chemistry Amines Properties of Amines

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What is the product of the following reaction?

AIIMS 2019 All AIIMS

A
$N$-ethylphthalimide
B
$N$,$N$'-diethylphthalamide
C
o-ethylcarbamoylbenzoic acid
D
Phthalic anhydride

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Class 12

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Amines

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Aniline $\xrightarrow[{{0^{\circ}}C - {5^{\circ}}C}]{{NaNO_2/HCl}}A$ $\xrightarrow{{Ph-N(CH_3)_2}}B$
What is $B$?

Medium

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Which isomer among the following has the highest boiling point?

EasyMHT CET 2023

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Match List $I$ with List $II$:
List $I$ (Amines) List $II$ $(pK_{b})$
$A$. Aniline $I$. $3.25$
$B$. Ethanamine $II$. $3.00$
$C$. $N$-Ethylethanamine $III$. $9.38$
$D$. $N,N$-Diethylethanamine $IV$. $3.29$

Choose the correct answer from the options given below:

DifficultJEE MAIN 2023

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Consider the reaction shown below. Compound $B$ is:

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The major product of the reaction is:
$R-CONH_2 \xrightarrow{NaOBr} (A)$
(where $R$ is the chiral group shown in the image)

Medium

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List $I$ (Amines)	List $II$ $(pK_{b})$
$A$. Aniline	$I$. $3.25$
$B$. Ethanamine	$II$. $3.00$
$C$. $N$-Ethylethanamine	$III$. $9.38$
$D$. $N,N$-Diethylethanamine	$IV$. $3.29$

What is the product of the following reaction?

Similar Questions

Aniline $\xrightarrow[{{0^{\circ}}C - {5^{\circ}}C}]{{NaNO_2/HCl}}A$ $\xrightarrow{{Ph-N(CH_3)_2}}B$What is $B$?

Which isomer among the following has the highest boiling point?

Match List $I$ with List $II$:List $I$ (Amines)List $II$ $(pK_{b})$$A$. Aniline$I$. $3.25$$B$. Ethanamine$II$. $3.00$$C$. $N$-Ethylethanamine$III$. $9.38$$D$. $N,N$-Diethylethanamine$IV$. $3.29$Choose the correct answer from the options given below:

Consider the reaction shown below. Compound $B$ is:

The major product of the reaction is: $R-CONH_2 \xrightarrow{NaOBr} (A)$ (where $R$ is the chiral group shown in the image)

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Aniline $\xrightarrow[{{0^{\circ}}C - {5^{\circ}}C}]{{NaNO_2/HCl}}A$ $\xrightarrow{{Ph-N(CH_3)_2}}B$
What is $B$?

Match List $I$ with List $II$:
List $I$ (Amines) List $II$ $(pK_{b})$
$A$. Aniline $I$. $3.25$
$B$. Ethanamine $II$. $3.00$
$C$. $N$-Ethylethanamine $III$. $9.38$
$D$. $N,N$-Diethylethanamine $IV$. $3.29$

Choose the correct answer from the options given below:

The major product of the reaction is:
$R-CONH_2 \xrightarrow{NaOBr} (A)$
(where $R$ is the chiral group shown in the image)