Let $PQR$ be a triangle in which $PQ=3$. From the vertex $R$,draw the altitude $RS$ to meet $PQ$ at $S$. Assume that $RS=\sqrt{3}$ and $PS=QR$. Then,$PR$ equals

  • A
    $\sqrt{5}$
  • B
    $\sqrt{6}$
  • C
    $\sqrt{7}$
  • D
    $\sqrt{8}$

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