Let $P(x_0, y_0)$ be the point on the hyperbola $3x^2 - 4y^2 = 36$ which is nearest to the line $3x + 2y = 1$. Then $\sqrt{2}(y_0 - x_0)$ is equal to:

  • A
    $-3$
  • B
    $9$
  • C
    $-9$
  • D
    $3$

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