Let A = begin{bmatrix} 12 & 24 & 5 x & 6 & 2 | vedclass

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(C) matrix $A$ is not invertible if and only if its determinant is zero, i.e.,$|A| = 0$. Given $A = \begin{bmatrix} 12 & 24 & 5 \ x & 6 & 2 \ -1 & -

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$3$

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(C) matrix $A$ is not invertible if and only if its determinant is zero, i.e.,$|A| = 0$. Given $A = \begin{bmatrix} 12 & 24 & 5 \ x & 6 & 2 \ -1 & -2 & 3 \end{bmatrix}$. Calculating the determinant $|A|$: $|A| = 12(6 	imes 3 - 2 	imes (-2)) - 24(x 	imes 3 - 2 	imes (-1)) + 5(x 	imes (-2) - 6 	imes (-1))$ $|A| = 12(18 + 4) - 24(3x + 2) + 5(-2x + 6)$ $|A| = 12(22) - 72x - 48 - 10x + 30$ $|A| = 264 - 82x - 18$ $|A| = 246 - 82x$ Setting $|A| = 0$: $246 - 82x = 0$ $82x = 246$ $x = \frac{246}{82} = 3$ Therefore, the value of $x$ is $3$.

Let $A = \begin{bmatrix} 12 & 24 & 5 \\ x & 6 & 2 \\ -1 & -2 & 3 \end{bmatrix}$. The value of $x$ for which the matrix $A$ is not invertible is

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