Let A be an invertible square matrix of order | vedclass

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(C) We know that the fundamental property of the adjoint of a matrix is $(	ext{adj} A) \cdot A = |A|I$, where $I$ is the identity matrix of order $3

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$|A|^3$

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(C) We know that the fundamental property of the adjoint of a matrix is $(	ext{adj} A) \cdot A = |A|I$, where $I$ is the identity matrix of order $3 	imes 3$.Taking the determinant on both sides, we get $|(	ext{adj} A) \cdot A| = ||A|I|$.Since $|A|$ is a scalar, we use the property $|kA| = k^n|A|$, where $n$ is the order of the matrix.Here, $n = 3$, so $|(	ext{adj} A) \cdot A| = |A|^3 |I|$.Since the determinant of an identity matrix $|I| = 1$, we have $|(	ext{adj} A) \cdot A| = |A|^3 	imes 1 = |A|^3$.

Let $A$ be an invertible square matrix of order $3 \times 3$. Then $|(\text{adj} A) \cdot A|$ is

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