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(C) Given that the angle between $\overrightarrow{A}$ and $\overrightarrow{B}$ is $	heta = 120^{\circ}$.The magnitude of the resultant $\overrightarr

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$\overrightarrow{C}$ must be less than $|\overrightarrow{A} - \overrightarrow{B}|$

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(C) Given that the angle between $\overrightarrow{A}$ and $\overrightarrow{B}$ is $	heta = 120^{\circ}$.The magnitude of the resultant $\overrightarrow{C} = \overrightarrow{A} + \overrightarrow{B}$ is given by:$|\overrightarrow{C}| = \sqrt{A^{2} + B^{2} + 2AB \cos 120^{\circ}} = \sqrt{A^{2} + B^{2} - AB}$.The magnitude of the difference vector $|\overrightarrow{A} - \overrightarrow{B}|$ is given by:$|\overrightarrow{A} - \overrightarrow{B}| = \sqrt{A^{2} + B^{2} - 2AB \cos 120^{\circ}} = \sqrt{A^{2} + B^{2} - 2AB (-1/2)} = \sqrt{A^{2} + B^{2} + AB}$.Comparing the two expressions,since $A$ and $B$ are nonzero magnitudes,$\sqrt{A^{2} + B^{2} - AB} Therefore,$|\overrightarrow{C}| < |\overrightarrow{A} - \overrightarrow{B}|$.

Let the angle between two nonzero vectors $\overrightarrow{A}$ and $\overrightarrow{B}$ be $120^{\circ}$ and their resultant be $\overrightarrow{C}$. Which of the following is true?

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