Match List-I with List-II :List-IList-IIA. Is | vedclass

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(B) The change in internal energy is given by $\Delta U = nC_{v} \Delta T$.For an isothermal process, the temperature $T$ is constant, so $\Delta T =

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$A-II, B-I, C-IV, D-III$

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(B) The change in internal energy is given by $\Delta U = nC_{v} \Delta T$.For an isothermal process, the temperature $T$ is constant, so $\Delta T = 0$, which implies $\Delta U = 0$. Thus, $A \longrightarrow II$.For an adiabatic process, the heat exchange $\Delta Q = 0$. According to the first law of thermodynamics, $\Delta Q = \Delta U + \Delta W$, so $\Delta U = -\Delta W$. If work is done by the gas, $\Delta W > 0$, then $\Delta U For an isochoric process, the volume $V$ is constant, so $\Delta V = 0$. Since work done $\Delta W = P \Delta V$, no work is done on or by the gas. Thus, $C \longrightarrow IV$.For an isobaric process, the pressure $P$ is constant. The heat absorbed $\Delta Q$ is used to both increase the internal energy $\Delta U$ and perform work $\Delta W = P \Delta V$. Thus, $D \longrightarrow III$.Therefore, the correct matching is $A-II, B-I, C-IV, D-III$.

List-$I$	List-$II$
$A$. Isothermal Process	$I$. Work done by the gas decreases internal energy
$B$. Adiabatic Process	$II$. No change in internal energy
$C$. Isochoric Process	$III$. The heat absorbed goes partly to increase internal energy and partly to do work
$D$. Isobaric Process	$IV$. No work is done on or by the gas

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