Match the items in List-$I$ with the items in List-$II$ and select the correct code:
List-$I$ List-$II$
$A$. Tollen's reagent $I$. Para-rosaniline + $SO_2$
$B$. Schiff's reagent $II$. Rochelle salt + $aq. NaOH$
$C$. Rosenmund reduction $III$. Ammoniacal silver nitrate
$D$. Fehling solution $B$ $IV$. $Pd + BaSO_4$

  • A
    $A-III, B-I, C-IV, D-II$
  • B
    $A-II, B-III, C-I, D-IV$
  • C
    $A-I, B-III, C-IV, D-II$
  • D
    $A-II, B-IV, C-III, D-I$

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Similar Questions

If the general formula of oxime and semicarbazone is $C=N-Z$,what is '$Z$' in oxime $(I)$ and semicarbazone $(II)$?

Consider the following reaction,where:
$(A)$ The change in the functional group and
$(B)$ The corresponding change in the hybridization from the starting material to the final product are:
$CH_3-C \equiv N \xrightarrow[(ii) \ HI + \text{Red } P]{(i) \ SnCl_2, HCl / H_3O^{+}}$

Which reagent is suitable for the following transformation?

$C_6H_5CHO + HCN \rightarrow C_6H_5CH(OH)CN$. The product formed is:

Match the examples given in Column $I$ with the name of the reaction in Column $II$ and identify the correct matches.
Column $I$ $(Example)$ Column $II$ $(Reaction)$
$a$. $CH_3COCl + H_2 \xrightarrow{Pd-C/BaSO_4} CH_3CHO$ Stephen's reaction
$b$. $C_6H_5CHO \xrightarrow{NaOH, \Delta} C_6H_5CH_2OH + C_6H_5COO^-Na^+$ Cannizzaro's reaction
$c$. $C_6H_6 + CH_3COCl \xrightarrow{AlCl_3} C_6H_5COCH_3$ Friedel-Crafts acylation
$d$. $R-CH_2-COOH \xrightarrow[H_2O]{Br_2/Red P} R-CH(Br)-COOH$ $HVZ$ reaction
$e$. $CH_3-CN \xrightarrow[\text{(ii) } H_2O/H^+]{\text{(i) } SnCl_2/HCl} CH_3CHO$ Stephen's reaction
$f$. $2 CH_3CHO \xrightarrow[\Delta]{NaOH} CH_3-CH=CHCHO$ Aldol condensation

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