Maximum number of molecules of CH_3I that can | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $CH_3NH_2$ reacts with $CH_3I$ through a process called exhaustive alkylation (Hofmann's alkylation). The reaction proceeds as follows: $1. CH_3NH

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) $CH_3NH_2$ reacts with $CH_3I$ through a process called exhaustive alkylation (Hofmann's alkylation). The reaction proceeds as follows: $1. CH_3NH_2 + CH_3I \rightarrow (CH_3)_2NH + HI$ (Secondary amine) $2. (CH_3)_2NH + CH_3I \rightarrow (CH_3)_3N + HI$ (Tertiary amine) $3. (CH_3)_3N + CH_3I \rightarrow (CH_3)_4N^+I^-$ (Quaternary ammonium salt) Thus,a total of $3$ molecules of $CH_3I$ react with one molecule of $CH_3NH_2$ to reach the final stable product.

Maximum number of molecules of $CH_3I$ that can react with a molecule of $CH_3NH_2$ are

Similar Questions

Phenyl isocyanide is prepared by which of the following reactions?

In the chemical reaction given above,$A$ and $B$ respectively are:

Aniline $\xrightarrow[{{0^{\circ}}C - {5^{\circ}}C}]{{NaNO_2/HCl}}A$ $\xrightarrow{{Ph-N(CH_3)_2}}B$
What is $B$?

Arrange the following compounds in increasing order of their basicity:
$CH_3NH_2, (CH_3)_2NH, C_6H_5NH_2, (CH_3)_3N$

In the chemical reactions,the compounds $A$ and $B$ respectively are

Vedclass Test Series

Exam Paper Generator

Online Exam Module