Obtain the expression for work done by a gas | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In an isobaric process,the pressure $P$ of the system remains constant throughout the process.Work done $W$ by a gas is defined by the integral $W

Vedclass · Accepted Answer

$W$ = $P$(V_f - V_i)

Vedclass · Answer

(A) In an isobaric process,the pressure $P$ of the system remains constant throughout the process.Work done $W$ by a gas is defined by the integral $W = \int_{V_i}^{V_f} P \, dV$.Since $P$ is constant,it can be taken out of the integral: $W = P \int_{V_i}^{V_f} dV$.Evaluating the integral,we get $W = P [V]_{V_i}^{V_f}$.Thus,the work done is $W = P(V_f - V_i)$,where $V_f$ is the final volume and $V_i$ is the initial volume.

Obtain the expression for work done by a gas during an isobaric process (constant pressure).

Similar Questions

$A$ container having $1 \ mol$ of a gas at a temperature of $27 \ ^oC$ has a movable piston which maintains a constant pressure of $1 \ atm$ in the container. The gas is compressed until the temperature becomes $127 \ ^oC$. The work done is ........ $J$ $(R = 8.31 \ J/mol-K)$.

$A$ diatomic gas $(\gamma=1.4)$ does $100 \,J$ of work in an isobaric expansion. The heat given to the gas is: (in $\,J$)

Which relation is correct for an isochoric process?

The percentage of heat supplied to a diatomic ideal gas that is converted into work in an isobaric process is

$A$ diatomic gas,having $C_{p} = \frac{7}{2} R$ and $C_{v} = \frac{5}{2} R$,is heated at constant pressure. The ratio $dU : dQ : dW$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module