Out of $21$ tickets marked with numbers from $1$ to $21$,three are drawn at random. The chance that the numbers on them are in $A.P.$ is

  • A
    $\frac{10}{133}$
  • B
    $\frac{9}{133}$
  • C
    $\frac{9}{1330}$
  • D
    None of these

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