Phenol + (HCN + HCl) xrightarrow[(2),,{H_2}O] | vedclass

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(C) The reaction of phenol with $HCN$ and $HCl$ in the presence of $ZnCl_2$ is a variation of the Gattermann formylation reaction. This reaction intro

Vedclass · Accepted Answer

$4-$hydroxybenzaldehyde

Vedclass · Answer

(C) The reaction of phenol with $HCN$ and $HCl$ in the presence of $ZnCl_2$ is a variation of the Gattermann formylation reaction. This reaction introduces a formyl group $(-CHO)$ onto the benzene ring of phenol,primarily at the para position due to the activating and ortho/para-directing nature of the $-OH$ group. The reaction proceeds via the formation of an imine intermediate,which upon hydrolysis with water $(H_2O)$ yields the corresponding aldehyde. Therefore,the product $X$ is $4$-hydroxybenzaldehyde.

Phenol $+ (HCN + HCl) \xrightarrow[(2)\,\,{H_2}O]{(1)\,ZnCl_2} X$ ; $X$ is

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