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(C) The amplification factor $\mu$ of a triode is defined as the ratio of the change in plate voltage to the change in grid voltage required to keep t

Vedclass · Accepted Answer

$33.3$

Vedclass · Answer

(C) The amplification factor $\mu$ of a triode is defined as the ratio of the change in plate voltage to the change in grid voltage required to keep the plate current constant.$\mu = \left( \frac{\Delta V_p}{\Delta V_g} ight)_{i_p = 	ext{constant}}$Given:$\Delta V_p = 225 \, V - 200 \, V = 25 \, V$$\Delta V_g = 5.75 \, V - 5 \, V = 0.75 \, V$Substituting the values:$\mu = \frac{25}{0.75} = \frac{2500}{75} = 33.33$Thus,the amplification factor is $33.3$.

The plate voltage of a triode is increased from $200 \, V$ to $225 \, V$. To maintain the plate current,a change in grid voltage from $5 \, V$ to $5.75 \, V$ is required. The amplification factor is:

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