The product $(B)$ of the reaction is:

The product $A$ obtained in the following reaction is:

What will be the product obtained when formaldehyde is treated with conc. $NaOD$ followed by treatment with conc. $H_2SO_4$?

The relation between $K_1$ and $K_2$ for the given equilibrium reactions is:

Which of the following compounds undergoes aldol condensation?

$(A)$ $\xrightarrow{NH_2OH} (B)$ $\xrightarrow{H_2SO_4} (C)$ $\xrightarrow{H_3O^{\oplus}} (D) + (E)$ $\xrightarrow{CHCl_3, KOH} CH_3-NC$ (carbylamine test). $(D)$ $\xrightarrow{SOCl_2} (F)$ $\xrightarrow{(i) PhMgBr \text{ (excess) } (ii) H^{\oplus}} (G)$ $\xrightarrow[\Delta]{H^{\oplus}} (H)$ $\xrightarrow{CH_2I_2, Zn/Cu} \text{1,1-diphenylcyclopropane}$. The molecular weight of compound $(A)$ is: