Product $(B)$ of this reaction is:

The product $(Y)$ of the following reaction is:

Consider the following sequence of reactions:
Chlorobenzene $\xrightarrow[ii) CO_2, H_3O^{+}]{i) Mg, \text{dry ether}} \text{Benzoic acid}$ $\xrightarrow{NH_3, \Delta} \text{Benzamide (A)}$ $\xrightarrow{Br_2, NaOH} \text{Aniline (B)}$
$11.25 \ mg$ of chlorobenzene will produce $.......... \times 10^{-1} \ mg$ of product $B$.
(Consider the reactions result in complete conversion.)
[Given molar mass of $C, H, O, N$ and $Cl$ as $12, 1, 16, 14$ and $35.5 \ g \ mol^{-1}$ respectively]

Predict the stereochemistry of the product when a $d$ and $l$-amine mixture reacts with an $l$-acid.

$X \ g$ of ethanamine was subjected to reaction with $NaNO_2 / HCl$ followed by hydrolysis to liberate $N_2$ and $HCl$. The $HCl$ generated was completely neutralized by $0.2 \ mol$ of $NaOH$. $X$ is . . . .

$NBS \xrightarrow{KOBr} (A)$. The product $(A)$ is: