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(D) The starting material is $3$-methylbutan-$2$-amine,which is a primary aliphatic amine. When a primary aliphatic amine reacts with nitrous acid $(H

Vedclass · Accepted Answer

All of these

Vedclass · Answer

(D) The starting material is $3$-methylbutan-$2$-amine,which is a primary aliphatic amine. When a primary aliphatic amine reacts with nitrous acid $(HNO_2)$,it forms a highly unstable diazonium salt. This diazonium salt rapidly loses nitrogen gas $(N_2)$ to form a carbocation. In this case,the initial carbocation formed is a secondary carbocation: $(CH_3)_2CH-CH^+(CH_3)$. This secondary carbocation can undergo a $1,2$-hydride shift to form a more stable tertiary carbocation: $(CH_3)_2C^+-CH_2CH_3$. Both the secondary and tertiary carbocations can be attacked by water $(H_2O)$ to form alcohols. The secondary carbocation leads to $3$-methylbutan-$2$-ol,and the tertiary carbocation leads to $2$-methylbutan-$2$-ol. Therefore,a mixture of products is formed,including $3$-methylbutan-$2$-ol and $2$-methylbutan-$2$-ol. Since the question asks for the product $(A)$ and lists multiple possibilities,the correct answer is that all of these (or a mixture) can be formed.

List-$I$ (Amine)	List-$II$ ($pK_b$ value)
$A$. $N,N$-Dimethylaniline	$I$. $9.30$
$B$. Aniline	$II$. $8.92$
$C$. $N$-Ethylethanamine	$III$. $9.38$
$D$. $N$-Methylaniline	$IV$. $3.00$

The product $(A)$ is:

Similar Questions

What is the total number of possible amines (excluding stereoisomers) for the molecular formula $C_3H_9N$?

Product $(B)$ of this reaction is:

Which set of products will be obtained in the following reactions?
$RCN \xrightarrow{\text{reduction}} (a)$
$RCN \xrightarrow[(ii) H_2O]{(i) CH_3MgBr} (b)$
$RNC \xrightarrow{\text{hydrolysis}} (c)$
$RNH_2 \xrightarrow{HNO_2} (d)$

Match the following:
List-$I$ (Amine) List-$II$ ($pK_b$ value)
$A$. $N,N$-Dimethylaniline $I$. $9.30$
$B$. Aniline $II$. $8.92$
$C$. $N$-Ethylethanamine $III$. $9.38$
$D$. $N$-Methylaniline $IV$. $3.00$

The correct answer is

The product $(C)$ of the following reaction is:

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