The products obtained in the given reactions are shown below. The number of possible products for $x$ and $y$ are:

  • A
    $1, 1$
  • B
    $1, 2$
  • C
    $2, 1$
  • D
    $2, 2$

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Product $(G)$ is

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The product $D$ of the reaction is:
$CH_3Cl$ $\xrightarrow{KCN} (A)$ $\xrightarrow{H_2O} (B)$ $\xrightarrow{NH_3} (C)$ $\xrightarrow{\Delta} (D)$

The incorrect match is:

Compound $A$ was treated with a large excess of $CH_3MgBr$. The resulting product was exposed to $POCl_3$ /pyridine to give compound $B$,as one of many products.
Which of the following compounds can be $A$ ?

In the given reaction: $NH_2-CH_2-CH_2-NH_2 + C_2H_5OOC-COOC_2H_5 \xrightarrow{\text{Pyridine}} [X]$,$[X]$ will be:

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