Select the CORRECT increasing order of boilin | vedclass

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Question

(A) The boiling point depends on the strength of intermolecular forces,primarily hydrogen bonding. $N-H$ bonds in amines are less polar than $O-H$ bon

Vedclass · Accepted Answer

$Amines < Alcohols < Carboxylic \ acids$

Vedclass · Answer

(A) The boiling point depends on the strength of intermolecular forces,primarily hydrogen bonding. $N-H$ bonds in amines are less polar than $O-H$ bonds in alcohols,leading to weaker hydrogen bonding in amines. Carboxylic acids contain a $-COOH$ group,which allows for the formation of stable dimeric structures through strong intermolecular hydrogen bonding. Therefore,the strength of hydrogen bonding follows the order: $Amines Consequently,the increasing order of boiling points is $Amines < Alcohols < Carboxylic \ acids$.

$a$. $\text{Toluene} \xrightarrow[(ii) H^+/H_2O]{(i) CrO_2Cl_2/CS_2}$	$p$. $\text{Kolbe's electrolysis}$
$b$. $CH_3COOK \xrightarrow{\text{electrolysis}}$	$q$. $\text{Etard reaction}$
$c$. $CH_3Br \xrightarrow{Na, \text{dry ether}}$	$r$. $\text{Wurtz reaction}$
$d$. $\text{Benzene} \xrightarrow{CH_3Cl, AlCl_3}$	$s$. $\text{Friedel-Crafts alkylation}$

Select the $CORRECT$ increasing order of boiling points of alcohols,amines,and carboxylic acids of comparable molar mass from the following.

Similar Questions

The major product in the following reaction is

$CH_3COOH \xrightarrow{LiAlH_4} A$
$A + CH_3COOH \xrightarrow{H_3O^+} B + H_2O$
In the above reactions,'$A$' and '$B$' respectively are:

In the following reaction,$X$ and $Y$ are respectively
$CH_3 COOH + NH_3$ $\longrightarrow X \stackrel{\Delta}{}$ ${\longrightarrow} Y + H_2 O$

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