Solubility products (K_{sp}) of the salts of | vedclass

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(D) For $MX$: $K_{sp} = S^2 = 4.0 	imes 10^{-8} \Rightarrow S = 2 	imes 10^{-4} 	ext{ mol dm}^{-3}$.For $MX_2$: $K_{sp} = 4S^3 = 3.2 	imes 10^{-14

Vedclass · Accepted Answer

$MX > M_3X > MX_2$

Vedclass · Answer

(D) For $MX$: $K_{sp} = S^2 = 4.0 	imes 10^{-8} \Rightarrow S = 2 	imes 10^{-4} 	ext{ mol dm}^{-3}$.For $MX_2$: $K_{sp} = 4S^3 = 3.2 	imes 10^{-14}$ $\Rightarrow S^3 = 8 	imes 10^{-15}$ $\Rightarrow S = 2 	imes 10^{-5} 	ext{ mol dm}^{-3}$.For $M_3X$: $K_{sp} = 27S^4 = 2.7 	imes 10^{-15}$ $\Rightarrow S^4 = 10^{-16}$ $\Rightarrow S = 1 	imes 10^{-4} 	ext{ mol dm}^{-3}$.Comparing the solubilities: $2 	imes 10^{-4} > 1 	imes 10^{-4} > 2 	imes 10^{-5}$.Thus, the order of solubility is $MX > M_3X > MX_2$.

Solubility products $(K_{sp})$ of the salts of types $MX, MX_2$ and $M_3X$ at temperature $T$ are $4.0 \times 10^{-8}, 3.2 \times 10^{-14}$ and $2.7 \times 10^{-15}$ respectively. Solubilities (in $mol \text{ dm}^{-3}$) of the salts at temperature $T$ are in the order:

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