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(A) For equation $I$: $5x^{2} + 2x - 3 = 0$Using the splitting the middle term method: $5x^{2} + 5x - 3x - 3 = 0$$5x(x + 1) - 3(x + 1) = 0$$(5x - 3)(x

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if $x > y$

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(A) For equation $I$: $5x^{2} + 2x - 3 = 0$Using the splitting the middle term method: $5x^{2} + 5x - 3x - 3 = 0$$5x(x + 1) - 3(x + 1) = 0$$(5x - 3)(x + 1) = 0$So,$x = 0.6$ or $x = -1$.For equation $II$: $2y^{2} + 7y + 6 = 0$Using the splitting the middle term method: $2y^{2} + 4y + 3y + 6 = 0$$2y(y + 2) + 3(y + 2) = 0$$(2y + 3)(y + 2) = 0$So,$y = -1.5$ or $y = -2$.Comparing the values:If $x = 0.6$,then $x > y$ (since $0.6 > -1.5$ and $0.6 > -2$).If $x = -1$,then $x > y$ (since $-1 > -1.5$ and $-1 > -2$).In all cases,$x > y$.

Solve the given two equations and select the correct answer from the given options.
$I.$ $5x^{2} + 2x - 3 = 0$
$II.$ $2y^{2} + 7y + 6 = 0$

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Solve the given two equations and select the correct answer from the given options.$I.$ $5x^{2} + 2x - 3 = 0$$II.$ $2y^{2} + 7y + 6 = 0$