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(D) Multiply equation $(I)$ by $5$ and equation $(II)$ by $8$:$40x + 35y = 675$$40x + 48y = 792$Subtracting the first from the second:$(40x + 48y) - (

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if $x = y > z$

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(D) Multiply equation $(I)$ by $5$ and equation $(II)$ by $8$:$40x + 35y = 675$$40x + 48y = 792$Subtracting the first from the second:$(40x + 48y) - (40x + 35y) = 792 - 675$$13y = 117 \Rightarrow y = 9$Substitute $y = 9$ into equation $(I)$:$8x + 7(9) = 135 \Rightarrow 8x + 63 = 135 \Rightarrow 8x = 72 \Rightarrow x = 9$Substitute $y = 9$ into equation $(III)$:$9(9) + 8z = 121 \Rightarrow 81 + 8z = 121 \Rightarrow 8z = 40 \Rightarrow z = 5$Comparing the values: $x = 9, y = 9, z = 5$.Therefore,$x = y > z$.

Solve the given equations and select the correct option.
$I.$ $8x + 7y = 135$
$II.$ $5x + 6y = 99$
$III.$ $9y + 8z = 121$

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Solve the given equations and select the correct option.$I.$ $8x + 7y = 135$$II.$ $5x + 6y = 99$$III.$ $9y + 8z = 121$