Strong reducing and oxidizing agents among th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In the lanthanoid series,$Eu^{2+}$ (europium$(II)$) is a strong reducing agent because it tends to lose an electron to achieve the stable $f^7$ co

Vedclass · Accepted Answer

$Eu^{2+}$ and $Ce^{4+}$

Vedclass · Answer

(D) In the lanthanoid series,$Eu^{2+}$ (europium$(II)$) is a strong reducing agent because it tends to lose an electron to achieve the stable $f^7$ configuration $(Eu^{3+})$.$Ce^{4+}$ (cerium$(IV)$) is a strong oxidizing agent because it tends to gain an electron to achieve the stable $f^0$ configuration $(Ce^{3+})$.Therefore,the correct pair is $Eu^{2+}$ and $Ce^{4+}$.

Strong reducing and oxidizing agents among the following,respectively,are

Similar Questions

Which one of the following species is stable in aqueous solution?

The highest stable $Mn$ fluoride is $MnF_4$,whereas the highest $Mn$ oxide is $Mn_2O_7$. This is due to:

What is the use of potassium permanganate $(KMnO_4)$?

Corundum is

Which of the following is amphoteric?

Vedclass Test Series

Exam Paper Generator

Online Exam Module