Taking the set of natural numbers as the univ | vedclass

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(B) Let $U = N = \{ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, \dots \}$ be the universal set of natural numbers.Let $A = \{ x : x 	ext{ is a prime number} \} =

Vedclass · Accepted Answer

$B = \{ x : x 	ext{ is a composite number or } x = 1 \}$

Vedclass · Answer

(B) Let $U = N = \{ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, \dots \}$ be the universal set of natural numbers.Let $A = \{ x : x 	ext{ is a prime number} \} = \{ 2, 3, 5, 7, 11, \dots \}$.The complement of set $A$,denoted by $A^\prime$,is defined as $A^\prime = U - A$.$A^\prime = \{ x : x \in N 	ext{ and } x 	ext{ is not a prime number} \}$.Since $1$ is neither prime nor composite,and all other natural numbers are either prime or composite,the set of non-prime natural numbers includes $1$ and all composite numbers.Therefore,$A^\prime = \{ x : x 	ext{ is a composite number or } x = 1 \}$.

Taking the set of natural numbers as the universal set,write down the complement of the following set:
$A = \{ x : x \text{ is a prime number} \}$

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Taking the set of natural numbers as the universal set,write down the complement of the following set:$A = \{ x : x \text{ is a prime number} \}$