The pH of water at 25,^oC is nearly | vedclass

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Question

(B) At $25\,^oC$,pure water is neutral,meaning the concentration of hydrogen ions is equal to the concentration of hydroxide ions: $[H^{+}] = [OH^{-}]

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(B) At $25\,^oC$,pure water is neutral,meaning the concentration of hydrogen ions is equal to the concentration of hydroxide ions: $[H^{+}] = [OH^{-}]$.The ionic product of water $(K_w)$ is $1.0 	imes 10^{-14}$.Thus,$[H^{+}] 	imes [OH^{-}] = 10^{-14}$,which implies $[H^{+}]^2 = 10^{-14}$,so $[H^{+}] = 10^{-7} \, M$.The $pH$ is calculated as $pH = -\log[H^{+}] = -\log(10^{-7}) = 7$.

The $pH$ of water at $25\,^oC$ is nearly

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