The degree of dissociation of a 0.01 M weak | vedclass

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(C) The concentration of hydrogen ions $[H^{+}]$ is given by the product of the degree of dissociation $(\alpha)$ and the molar concentration $(C)$.$[

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(C) The concentration of hydrogen ions $[H^{+}]$ is given by the product of the degree of dissociation $(\alpha)$ and the molar concentration $(C)$.$[H^{+}] = \alpha \cdot C = 10^{-3} \cdot 0.01 = 10^{-5} \ M$.Now,calculate the $pH$ using the formula $pH = -\log [H^{+}]$.$pH = -\log(10^{-5}) = 5$.Finally,calculate the $pOH$ using the relation $pH + pOH = 14$.$pOH = 14 - 5 = 9$.

The degree of dissociation of a $0.01 \ M$ weak acid is $10^{-3}$. Its $pOH$ is

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