The pH of a buffer solution obtained by mixin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given solution is a basic buffer consisting of a weak base $(NH_4OH)$ and its salt with a strong acid $(NH_4Cl)$.Using the Henderson-Hasselbal

Vedclass · Accepted Answer

$8.2$

Vedclass · Answer

(C) The given solution is a basic buffer consisting of a weak base $(NH_4OH)$ and its salt with a strong acid $(NH_4Cl)$.Using the Henderson-Hasselbalch equation for a basic buffer:$pOH = pK_b + \log \frac{[Salt]}{[Base]}$First,calculate the number of millimoles:$n(NH_4OH) = 50 \ mL 	imes 0.1 \ M = 5 \ mmol$$n(NH_4Cl) = 25 \ mL 	imes 2.0 \ M = 50 \ mmol$Since the total volume is $75 \ mL$,the concentrations are $[Salt] = \frac{50}{75} \ M$ and $[Base] = \frac{5}{75} \ M$.Substituting these into the equation:$pOH = 4.8 + \log \frac{50/75}{5/75} = 4.8 + \log(10) = 4.8 + 1 = 5.8$Now,calculate $pH$ using $pH + pOH = 14$:$pH = 14 - 5.8 = 8.2$

The $pH$ of a buffer solution obtained by mixing $50 \ mL$ of $0.1 \ M$ $NH_4OH$ and $25 \ mL$ of $2.0 \ M$ $NH_4Cl$ is ($pK_b$ of $NH_4OH$ is $4.8$).

Similar Questions

How to prepare a buffer solution using ammonia $(pK_b = 4.75)$? What is the $pH$ of this buffer if the concentrations of ammonia and ammonium chloride are equal?

$A$ buffer solution has equal volumes of $0.2 \ M \ NH_4OH$ and $0.02 \ M \ NH_4Cl$. The $pK_b$ of the base is $5$. The $pH$ is

Calculate the molar ratio of a weak acid $HA$ $(K_a=10^{-6})$ and its salt with a strong base,so that the $pH$ of the buffer solution is $6$.

Which of the following solutions does not act as a buffer $:-$

$A$ solution of $H_3BO_3$ and borax is known as:

Vedclass Test Series

Exam Paper Generator

Online Exam Module