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If the pair of lines $ax^2 + 2(a + b)xy + by^2 = 0$ lie along diameters of a circle and divide the circle into four sectors such that the area of one of the sectors is thrice the area of another sector,then:

Four different pairs of lines are given in List-$I$ and the cosine of the angle between every pair of lines is given in List-$II$. Match the following:
List-$I$List-$II$
$(A)$ $5x^2 + 2\sqrt{7}xy - y^2 = 0$$(I)$ $\frac{\sqrt{3}}{2}$
$(B)$ $x^2 + \sqrt{11}xy + 2y^2 = 0$$(II)$ $\frac{1}{2\sqrt{3}}$
$(C)$ $x^2 + 2\sqrt{2}xy + y^2 = 0$$(III)$ $\frac{1}{2}$
$(D)$ $3x^2 + 4\sqrt{2}xy + y^2 = 0$$(IV)$ $\frac{2}{3}$
$(V)$ $\frac{1}{\sqrt{2}}$

The correct match is:

The angle between the pair of lines represented by $x^2 + 2xy - y^2 = 0$ is:

The condition for the two lines represented by the equation $ax^2 + 2hxy + by^2 = 0$ to be perpendicular is:

The lines represented by $ax^2 + 2hxy + by^2 = 0$ are perpendicular to each other,if ........

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