The angle of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index $n$) is

$A$ ray of light is incident at the polarising angle $\theta$ on an air-glass interface. If $\lambda_a$ and $\lambda_g$ are the wavelengths of light in air and glass respectively, then:

$A$ ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle $\Phi$. If $\mu$ denotes the refractive index of glass with respect to air, then what will be the angle between the reflected and refracted rays?

$A$ ray of light is incident from a denser to a rarer medium. The critical angle for total internal reflection is $\theta_{iC}$ and Brewster's angle of incidence is $\theta_{iB}$,such that $\sin \theta_{iC} / \sin \theta_{iB} = \eta = 1.28$. The relative refractive index of the two media is

Unpolarised light is incident from air on a plane surface of a material of refractive index $\mu$. At a particular angle of incidence $i$,it is found that the reflected and refracted rays are perpendicular to each other. Which of the following options is correct for this situation?

For a given medium, the polarizing angle is $60^o$. What will be the critical angle for this medium?