The angular momentum of the orbital electron | vedclass

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Question

(C) According to Bohr's second postulate,an electron can only revolve in those orbits for which its angular momentum $L$ is an integral multiple of $\

Vedclass · Accepted Answer

$\frac{h}{2\pi}$

Vedclass · Answer

(C) According to Bohr's second postulate,an electron can only revolve in those orbits for which its angular momentum $L$ is an integral multiple of $\frac{h}{2\pi}$.Mathematically,this is expressed as $L = mvr = n\frac{h}{2\pi}$,where $n$ is an integer $(n = 1, 2, 3, ...)$,$h$ is Planck's constant,$m$ is the mass of the electron,$v$ is the velocity,and $r$ is the radius of the orbit.Thus,the angular momentum is an integral multiple of $\frac{h}{2\pi}$.

The angular momentum of the orbital electron is an integral multiple of:

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