The appropriate naming for the second step in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The haloform reaction involves three main steps: $1$. $\alpha$-halogenation: The $\alpha$-hydrogens of the carbonyl compound are replaced by halog

Vedclass · Accepted Answer

Dehydrohalogenation

Vedclass · Answer

(B) The haloform reaction involves three main steps: $1$. $\alpha$-halogenation: The $\alpha$-hydrogens of the carbonyl compound are replaced by halogen atoms. $2$. Hydrolysis (or cleavage): The trihalomethyl ketone formed in the first step undergoes nucleophilic attack by $OH^-$ followed by the cleavage of the $C-C$ bond to produce a carboxylate ion and a haloform $(CHX_3)$. $3$. Acid-base reaction: The haloform is formed. However, in many textbooks, the process of forming the haloform from the trihalomethyl intermediate is often categorized under the broader mechanism of nucleophilic acyl substitution or simply the cleavage step. Given the options provided, the reaction sequence is often described as $\alpha$-halogenation followed by the cleavage/hydrolysis step. Since the question asks for the naming of the second step in the context of the haloform reaction mechanism, and considering the options, the most accurate description of the transformation of the trihalomethyl ketone is the cleavage step, which is a type of nucleophilic substitution. If we look at the options, none perfectly describe the cleavage, but the reaction is often taught as $\alpha$-halogenation followed by the formation of the haloform. Given the standard options, if the question implies the overall process, the second step is the cleavage of the $C-C$ bond.

The appropriate naming for the second step in the haloform reaction is:

Similar Questions

Reductive amination of $A$ forms :
$A$ :

Cyanohydrin of which of the following forms lactic acid?

Which of the following compounds will not show tautomerism?

Identify product $B$ in the following reaction: $\text{Propanone}$ $\xrightarrow{\text{Ba(OH)}_2} A$ $\xrightarrow{\Delta, -\text{H}_2\text{O}} B$

Vedclass Test Series

Exam Paper Generator

Online Exam Module