(D) The area $A$ is given by the integral of $|y|$ with respect to $x$ from $x = -2$ to $x = 4$.$A = \int_{-2}^{4} |x| \, dx$Since $|x| = -x$ for $x <

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(D) The area $A$ is given by the integral of $|y|$ with respect to $x$ from $x = -2$ to $x = 4$.$A = \int_{-2}^{4} |x| \, dx$Since $|x| = -x$ for $x $A = \int_{-2}^{0} (-x) \, dx + \int_{0}^{4} x \, dx$$A = \left[ -\frac{x^2}{2} \right]_{-2}^{0} + \left[ \frac{x^2}{2} \right]_{0}^{4}$$A = (0 - (-\frac{(-2)^2}{2})) + (\frac{4^2}{2} - 0)$$A = (0 - (-2)) + (8 - 0)$$A = 2 + 8 = 10 \text{ square units}$.

Class 12 Mathematics Application of Integration Area bounded by region of single curve

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The area (in square units) bounded by the line $y = x$, the $X$-axis and the lines $x = -2$ and $x = 4$ is...

MHT CET 2026 All MHT CET

A
$6$
B
$\frac{15}{2}$
C
$\frac{17}{2}$
D
$10$

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Application of Integration

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Area bounded by region of single curve

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The area (in square units) bounded by the line $y = x$, the $X$-axis and the lines $x = -2$ and $x = 4$ is...

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