The area of the triangle with vertices at (-4 | vedclass

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(A) The area of a triangle with vertices $(x_1, y_1), (x_2, y_2), (x_3, y_3)$ is given by the formula:Area $= \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 -

Vedclass · Accepted Answer

$14$

Vedclass · Answer

(A) The area of a triangle with vertices $(x_1, y_1), (x_2, y_2), (x_3, y_3)$ is given by the formula:Area $= \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$Substituting the given vertices $(-4, 1), (1, 2), (4, -3)$:Area $= \frac{1}{2} |-4(2 - (-3)) + 1(-3 - 1) + 4(1 - 2)|$Area $= \frac{1}{2} |-4(5) + 1(-4) + 4(-1)|$Area $= \frac{1}{2} |-20 - 4 - 4|$Area $= \frac{1}{2} |-28| = 14$ square units.

The area of the triangle with vertices at $(-4, 1), (1, 2), (4, -3)$ is

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