The sides of a triangle are 4 , cm, 5 , cm an | vedclass

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(B) Given sides of the triangle are $a = 4 \, cm, b = 5 \, cm, c = 6 \, cm$. Semi-perimeter $s = \frac{a + b + c}{2} = \frac{4 + 5 + 6}{2} = \frac{15}

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$\frac{15}{4} \sqrt{7} \, cm^2$

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(B) Given sides of the triangle are $a = 4 \, cm, b = 5 \, cm, c = 6 \, cm$. Semi-perimeter $s = \frac{a + b + c}{2} = \frac{4 + 5 + 6}{2} = \frac{15}{2} \, cm$. Using Heron's formula,Area $= \sqrt{s(s - a)(s - b)(s - c)}$. Area $= \sqrt{\frac{15}{2} \left( \frac{15}{2} - 4 ight) \left( \frac{15}{2} - 5 ight) \left( \frac{15}{2} - 6 ight)}$. Area $= \sqrt{\frac{15}{2} 	imes \frac{7}{2} 	imes \frac{5}{2} 	imes \frac{3}{2}}$. Area $= \sqrt{\frac{15 	imes 7 	imes 15}{16}} = \frac{15}{4} \sqrt{7} \, cm^2$.

The sides of a triangle are $4 \, cm, 5 \, cm$ and $6 \, cm$. The area of the triangle is equal to

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